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Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients `x^2-2x-8`

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Best answer
`P(x)=x^2-2x-8`
=`x^2-4x+2x-8`
=`x(x-4)+2(x-1)`
=`(x+2)(x-4)`
now, let
`alpha=-4x and beta=x`
`alpha+beta=-2x`
`alpha*beta=-8x^2`
som of zeroes=`-(coefficient of

x)/(coefficient of x^2)`
=`-(-2)/1`
=2

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