According to given equation 1 mol of CaCO3 (s) requires 2 mol of HCl (aq). Hence, for the reaction of 10 mol of CaCO3 (s) number of moles of HCl required would be:
But we have only 0.19 mol HCl (aq), hence, HCl (aq) is limiting reagent. So amount of CaCl2 formed will depend on the amount of HCl available. Since, 2 mol HCl (aq) forms 1 mol of CaCl2, therefore, 0.19 mol of HCl (aq) would give: