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in Derivatives by (49.2k points)
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Let f(x) = \(\begin{cases} \frac{x^2-2x-3}{x+1^2},when\;x\neq-1 \\ k, when\;x=-1 \end{cases}\)

f(x) = (x2 - 2x - 3/x+12, when x ≠ -1), (k, when x = -1)

If f(x) is continuous at x = -1 then k = ?

A. 4

B. -4

C. -3

D. 2

1 Answer

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Best answer

Answer is : B. - 4

⇒ f(x) = \(\frac{x^2-2x-3}{x+1}\)is continuous at x = 0.

⇒ f(x) = - 4

∴ K = 1

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