Find dy/dx, when x = (1 - t^2)/(1 + t^2), y = 2t/ (1 + t^2)

Question

Find dy/dx, when x = \(\cfrac{1-t^2}{1+t^2}\), y = \(\cfrac{2t}{1+t^2}\)

(1 - t²)/(1 + t²),  2t/ (1 + t²)

Answer 1

Theorem: y and x are given in a different variable that is t. We can find dy/dx by finding dy/dt and dx/dt and then dividing them to get the required thing.