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If x = \(\cfrac{1+log\,t}{t^2}\) and y = \(\cfrac{3+2\,log\,t}t\)\(\cfrac{dy}{d\text x}\) = t.

(1 + log t)/t(3 + 2 log t)/t dy/dx

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Theorem: y and x are given in a different variable that is t. We can find dy/dx by finding dy/dt and dx/dt and then dividing them to get the required thing.

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