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If A = \( \begin{bmatrix} 2 & 3 \\[0.3em] 1& 2 \end{bmatrix}\)and f(x) = x2 – 4x + 1, find f(A).

A = [(2,3)(1,2)]

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Given, A = \( \begin{bmatrix} 2 &3 \\[0.3em] 1 & 2 \\[0.3em] \end{bmatrix}\)

f(x) = x2 – 4x + 1,

f(A) = A2 – 4A + I,

f(A) = \( \begin{bmatrix} 0 &0 \\[0.3em] 0& 0 \\[0.3em] \end{bmatrix}\)

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