Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
326 views
in Differential Equations by (37.0k points)
closed by

Find the general solution for \(xdy + ( y- x^3)\,dx = 0\)differential equations.

xdy + (y - x3) dx = 0

1 Answer

+1 vote
by (35.1k points)
selected by
 
Best answer

Given Differential Equation :

\(xdy + ( y- x^3)\,dx = 0\)

Formula :a

i) \(\int \frac{1}{x}\) dx = log x

ii) aloga b = b

iii) \(\int x ^n\,dx = \frac{x^{n+1}}{n+1}\)

iv) General solution :

For the differential equation in the form of

\(\frac{dy}{dx}\, + \, Py = Q \)

General solution is given by,

y. (I. F.) = \(\int\) Q. (I. F.) dx + c

Where, integrating factor,

I. F.= \(e^{\int p\, dx}\)

Given differential equation is

Equation (1) is of the form

\(\frac{dy}{dx} \, + Py\, = Q\)

Where, \(P= \frac{1}{x}\, and \, Q = x^2\)

Therefore, integrating factor is

General solution is

Dividing above equation by x,

∴ \(y = \frac{x^3}{4} + \frac{c}{x}\)

Therefore general equation is

 \(y = \frac{x^3}{4} + \frac{c}{x}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...