Given: A bag containing 10 white and 15 black balls .Each trial is independent of the other trial.
To find: the probability that the first ball is drawn is white and the second ball drawn is black.
Let , success in the first draw be getting a white ball.
Now , the Probability of success in the first trial is
P1(success) = \(\frac{10}{25}\)
Let success in the second draw be getting a black ball.
Probability of success in the second trial without replacement of the first draw is given by
P2(success) = \(\frac{15}{24}\)
Hence , the probability that the first ball is drawn is white and the second ball drawn is black,with each trial being independent is given by