Given: An urn containing 5 white and 8 black balls .Each trial is independent of the other trial
To find: the probability that the first draws gives 3 white and the second draw gives 3 black balls.
Let , success in the first draw be getting 3 white balls.
Now , the Probability of success in the first trial is
P1(success) = \(\frac{5{c_3}}{13c_3}=\frac{10}{286}=\frac{5}{143}\)
Let success in the second draw be getting 3 black balls.
Probability of success in the second trial without replacement of the first draw is given by
P2(success) = \(\frac{8{c_3}}{10c_3}=\frac{56}{120}=\frac{7}{15}\)
Hence , the probability that the first draws gives 3 white and the second draw gives 3 black balls,with each trial being independent is given by