**Given: **An urn containing 5 white and 8 black balls .Each trial is independent of the other trial

**To find: **the probability that the first draws gives 3 white and the second draw gives 3 black balls.

Let , success in the first draw be getting 3 white balls.

Now , the Probability of success in the first trial is

P_{1}(success) = \(\frac{5{c_3}}{13c_3}=\frac{10}{286}=\frac{5}{143}\)

Let success in the second draw be getting 3 black balls.

Probability of success in the second trial without replacement of the first draw is given by

P_{2}(success) = \(\frac{8{c_3}}{10c_3}=\frac{56}{120}=\frac{7}{15}\)

**Hence ,** the probability that the first draws gives 3 white and the second draw gives 3 black balls,with each trial being independent is given by