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If S is a point on side PQ of a Δ PQR such that PS = QS = RS, then

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If S is a point on side PQ of a Δ PQR such that PS = QS = RS, then

(A) PR . QR = RS2 (B) QS2 + RS2 = QR2

(C) PR2 + QR2 = PQ2 (D) PS2 + RS2 = PR2

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Correct answer is (C) PR2 + QR2 = PQ2

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