Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
77 views
in Differential Equations by (35.1k points)
closed by

The solution of the DE \(\frac{dy}{dx}\) = ex+y + x2 . ey is

A. ex-y\(\frac{x^3}{3}\) + C

B. ex + e-y  + \(\frac{x^3}{3}\) + C'

C.  ex - e-y  + \(\frac{x^3}{3}\) + C

D. None of these

1 Answer

+1 vote
by (37.0k points)
selected by
 
Best answer

Given \(\frac{dy}{dx}\) = ex+y + x2 e

On integrating on both sides, we get

Conclusion: Therefore, e-y + ex\(\frac{x^3}{3}\) = C is the 

solution of \(\frac{dy}{dx}\) = ex+y + x2ey

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...