Question

The solution of the DE x cos y dy = (xe^x log x + e^x ) dx is

A. sin y = e^x log x +C

B. sin y - e^x log x = C

C. sin y = e^x (log x) +C

D. none of these

Answer 1

On integrating on both sides we get

Conclusion: Therefore, sin y = e^x log x + c the solution of

x cos dy = (xe^x log x + e^x) dx