**Given:** Let A ,B , C and D be first second third and fourth shots whose probability of hitting the plane is given

i.e, P(A) = 0.4 ,P(B) = 0.3 , P(C) = 0.2 and P(D) = 0.1 respectively

\(\Rightarrow\) P(\(\overline A\)) = 0.6 and P(\(\overline B\)) = 0.7 and P(\(\overline C\)) = 0.8 and P(\(\overline D\)) = 0.9

**To Find: **The probability that atleast one shot hits the plane .

Here , P(atleast one shot hits the plane)

= 1 – P(none of the shots hit the plane)

= 0.6976

**Therefore,** The probability that atleast one shot hits the plane is 0.6976.