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in Differential Equations by (35.1k points)
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The general solution of the DE log \((\frac{dy}{dx})\) = (ax + by) is

A. \(\frac{-e^{by}}{b} = \frac{e^{ax}}{a}\) + C

B. eax -e-by = C

C. beax + aebe = C

D. None of these

1 Answer

+1 vote
by (37.0k points)
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Best answer

On integrating on both sides we get

Conclusion: Therefore, - \(\frac{e^{-by}}{b} = \frac{e^{ax}}{a}\) + C is the solution of

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