**Given : **let H be head, and T be tails where as 1,2,3,4,5,6

be the numbers on the dice which are thrown when a head comes up or else coin is tossed again if its tail.

**According to the question ,**

sample space S = {(TH),(TT) ,(H1),(H2),(H3),(H4),(H5),(H6)}

**To Find: **

**(i)** the probability of obtaining two tails

From sample space, it is clear that the probability of obtaining two tails is\(\frac{1}{8}\)

i.e., {TT} with total no of elements in sample space as 8.

**(ii)** the probability of obtaining a head and the number 6

From sample space, it is clear that the probability of obtaining a head and the number 6 is\(\frac{1}{8}\)

i.e., {H6} with total no of elements in sample space as 8.

**(iii)** the probability of obtaining a head and an even number

From sample space, it is clear that the probability of obtaining a head and an even number is\(\frac{3}{8}\)

i.e, {H2,H4,H6} with total no of elements in sample space as 8.