Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
129 views
in Differential Equations by (35.1k points)
closed by

The general solution of the DE \(\frac{dy}{dx} = \frac{y}{x} +\, sin\, \frac {y}{x}\) is

A. tan \(\frac{y}{2x}\) = Cx

B.  tan \(\frac{y}{x}\) = Cx

C.  tan \(\frac{y}{2x}\) = C

D. None of these

1 Answer

+1 vote
by (37.0k points)
selected by
 
Best answer

Conclusion: Therefore, tan \(\frac{y}{2x} \) = Cx is the solution of \(\frac{dy}{dx}\)v + x \(\frac{dv}{dx}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...