# An electromagnetic wave passing through vacuum is described by E = E0 sin(kx - ωt), B = B0 sin(kx - ωt). The correct equation is

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An electromagnetic wave passing through vacuum is described by E = E0 sin(kx - ωt), B = B0 sin(kx - ωt). The correct equation is

(a) E0B0 = ωk

(b) E0k = B0ω

(c) E0ω = B0k

(d) $\frac{k}{\omega}=\sqrt\frac{E_0}{B_0}$

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Answer is (b) E0k = B0ω