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in Mathematics by (22.7k points)

An aeroplane leaves an Airport and flies due North at 300 km/h. At the same time, another aeroplane leaves the same Airport and flies due West at 400 km/h. How far apart the two aeroplanes would be after 1 1/2 hours?

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Solution: 

Distance travelled by first aeroplane in

1 1/2 hours = 300 × 3/2 km = 450 km

and that by second aeroplane =

(400 × 3)/2 km =  600 km

Position of the two aeroplane after 1 1/2 hours would be A and B as shown in Fig. 6.14.

Thus, the two aeroplanes will be 750 km apart after1 1/2 hours.

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