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in Factorization by (15 points)
edited by

Factorize 

-X​​​​​​3+6x2​​​​-3x-10

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1 Answer

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\(-x^3+6x^2-3x-10\)

\(\because x=-1\) is a zero of this function.

Therefore \((x+1)\) is a factor of it.

Now,

\(-x^3+6x^2-3x-10\)

\(=(x+1)(-x^2+7x-10)\)

\(=(x+1)(-x^2+2x+5x-10)\)

\(=(x+1)(-x(x-2)+5(x-2))\)

\(=(x+1)(x-2)(-x+5)\)

\(=-(x+1)(x-2)(x-5)\)

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