Given: Equation of plane is 2x – y + z + 3 = 0. P is at (1, 3, 4)
To find: image of P
Explanation:
From the figure, P’ is the image of P and B is the midpoint of PP’
If B is (a, b, c), then
So any point on the line PB will be of the form
x = 2λ +1, y = -λ + 3, z = λ + 4
Since (a, b, c) will also be of this form we can substitute these values in (1)
⇒ 2(2λ + 1) – (-λ + 3) + (λ + 4) + 3 = 0
⇒ 4λ + 2 + λ – 3 + λ + 4 + 3 = 0
⇒ 6λ = -6
⇒ λ = -1
So (a, b, c) = (-1, 4, 3)
Substituting these values in the equations of a, b and c,
Therefore,
x1 = -3, y1 = 5, z1 = 2
Therefore, the image is (-3, 5, 2)