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Find the sum of first 24 terms of the A.P. a1, a2, a3, ... if it is known that a1 + a5 + a10 + a15 + a20 + a24 = 225

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We know that in an A.P., the sum of the terms equidistant from the beginning and end is always the same and is equal to the sum of first and last term.

Therefore, d = b – a

a1 + a24 = a5 + a20 = a10 + a15

It is given that

We know that

where a is the first term and l is the last term of an A.P.

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