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in Straight Lines by (15 points)
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Show that the line joining the points (2,-3) and (-5, 1) is Perpendicular to the line joining (4, 5) and (0, -2).

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2 Answers

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by (15 points)

m1*m2=-1

so,first you find L1 and L2 ,m

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by (49.2k points)

Slope of line joining the points (2, -3) and (-5, 1) is m1 \(=\frac{1-(-3)}{-5-2}=\frac{1+3}{-7}\) = -4/7

Slope of line joining the points (4, 5) and (0, -2) is m2 \(=\frac{-2-5}{0-4}=\frac{-7}{-4}\) = 7/4

Now, m1 m2\(\frac{-4}{7}\times\frac{7}{4}\) = -1

which is condition that both lines are perpendicular.

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