Lines AB and CD intersect at O.

∠AOC + ∠BOE = 70° (Given) …(1)

∠BOD = 40° (Given) …(2)

Since, ∠AOC = ∠BOD

(Vertically opposite angles)

Therefore, ∠AOC = 40° [From (2)]

and 40° + ∠BOE = 70° [From (1)]

⇒ ∠BOE = 70° – 40° = 30°

Also, ∠AOC + ∠BOE + ∠COE = 180°

(∵ AOB is a straight line)

70° + ∠COE = 180° [Form (1)]

⇒ ∠COE = 180° – 70° = 110°

Now, reflex ∠COE = 360° – 110° = 250°

Hence, ∠BOE = 30° and reflex ∠COE = 250° Ans