(i) (C) mg tanB, mg secB
(ii) (B) mg cosB
(iii) (D) zero
(iv) (A) g tanB, rightward
Now when string BC is cut;
Mass ‘m’ will just have force fall. Hence tension in string AB is zero.
Now suppose it is keep in a moving automobile;
In automobile’s frame of reference, there is a pseudo force acting on the mass.
The resultant force should be along BC.
Since its acting leftwards, the vehicle should move rightwards.