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A single bacterium is actively growing in a medium that supports its growth to a number of 100 million. Assuming the division time of the bacterium as 3 hours and the lifespan of non-dividing bacteria as 5 hours, which one of the following represents the maximum number of bacteria that would be present at the end of 15 hours?

(a) 10

(b) 64

(c) 24

(d) 32

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Answer is : (d) 32

The number of bacteria after 15 hours will be 32. This happens as each bacterium doubles up after every 3 hours, i.e. it will double 15/3 = 5 times in 15 hours.

Therefore, the sequence in which the growth of bacteria taking place will be

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