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in Mathematics by (50.7k points)
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Let a1, a2, a3, a4 be real numbers such that a1+a2+a3+a4 = 0 and a12+a22+a32+a42 = 1. Then, the smallest possible value of the expression (a1-a2)2 + (a2-a3)2 + (a3-a4) + (a4-a1)2 lies in the interval

(a) (0, 1.5)

(b) (1.5, 2.5)

(c) (2.5, 3)

(d) (3, 3.5)

1 Answer

+1 vote
by (49.2k points)
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Best answer

Answer is : (b) (1.5, 2.5)

It is possible only

The value lies between (1.5, 2.5).

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