Question

Figure shows a rod of length L pivoted near an end and which is made to rotate in a horizontal plane with a constant angular speed. A ball of mass ma is suspended by a string also of length L from the other end of the rod. If  θ is the angle made by sting with  the vertical, then

(A) T sinθ = mω² L( 1 + sinθ)

(B) T cosθ mg

(C) tan θ = \(\frac{\omega^2L(1+ sin \theta)}{g}\)

(D) None of above

Answer 1

Correct options are (A), (B) and (C)

Free body diagram of mass m;

Answer 2

Correct answer is

 (A) T sinθ = mω² L( 1 + sinθ)

(B) T cosθ mg

(C) tan θ = \(\frac{\omega^2L(1+ sin \theta)}{g}\)