Correct options are (B) and (D)
Consider the figure, with force F on the particle at different instants of time.
So it is evident that there should be some other forces such that particle will have uniform circular motion
\(\therefore \vec F + \vec F_2= m\vec a\)
Since it’s a uniform circular motion
Now resultant of both the forces \(\vec F\) and \(\vec F_2\) is \(\frac{mv^2}{r}\) which in turn keeps changing both in direction as well as magnitude.
∴ \(\vec F_2=\frac{mv^2}{r}\hat e_r - \vec F\)
Angle between \(\hat e_r\) and \(\vec F\) keeps varying.