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in Laws of motion by (15.3k points)
closed by

The bob of a simple pendulum is given a velocity 10m/s at its lowest point. Mass of the bob is 1kg and string length is 1 m.

Column I Column II
(A) Minimum tension in string (in Newton) (p) 50
(B) Magnitude of acceleration of bob when the string is horizontal (in m/s2) (q) 60
(C) Minimum magnitude of acceleration of bob (in m/s2) (r) zero
(D) Tangential acceleration at the highest point (in m/s2) (s) 10\(\sqrt{65}\)

2 Answers

+1 vote
by (39.0k points)
selected by
 
Best answer

A → p;  B → s;  C → q;  D → r

Energy at point A = 1/2 mvA2 (point A is assumed to be ground)

When string is horizontal i.e. at point B;

+1 vote
by (15.9k points)

A → p; 

B → s; 

C → q; 

D → r

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