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in Laws of motion by (15.3k points)
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A car of mass 500kg is moving in a circular road of radius 35 / √3 . Angle of the banking of road is 30. Coefficient of friction between road and tires is µ = \(\frac{1}{2\sqrt{3}}\)

Match the following:

Column I Column II
(A) Maximum speed (in m/s) of car for safe turning (p) 5\(\sqrt{2}\)
(B) Minimum speed (in m/s) of car for safe turning (q) 12.50
(C) Speed (in m/s) at which friction force between tires and road is zero (r) \(\sqrt{210}\)
(D) Friction force (in 10Newton) between tires and road if speed is \(\sqrt{\frac{350}{6}}\) m/s (s) \(\sqrt{\frac{350}{6}}\)

2 Answers

+1 vote
by (39.0k points)
selected by
 
Best answer

A → r; B → p; C → s; D → q

Now depending on condition, friction can be upwards or downwards.

For maximum speed, friction is downwards.

+1 vote
by (15.9k points)

A → r; 

B → p; 

C → s; 

D → q

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