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Water falls down a 500.0 m shaft to reach a turbine which generates electricity. How much water must fall per second in order to generate 1.00 x 109 W of power ? (Assume 50% efficiency of conversion and g =10 ms−2)

(a) 250 m3

(b) 400 m3

(c) 500 m3

(d) 200 m3

1 Answer

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Answer is : (b) 400 m3

Power output, P = 50% of potential energy of water

Received by generator per second

Substituting these values in Eq. (i), we get

Volume flow rate of water = V/t

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