Maximum friction between A and B = µmAg
or f1 = 0.25(3)(10) = 7.5 N
Maximum friction between B and C = µ(mA + mB)g
or f2 = 0.25 (3 + 4)(10) = 17 5 N
Maximum friction between C and ground
f3 = µ (mA + mB + mC)g
= 0.25(3 + 4 + 8)(10)
= 37.5 N
Block C and hence block B are moving in opposite directions with constant velocities and block A is at rest. Hence, net force no all three blocks should be zero. Free body diagrams have been shown below (Only horizontal forces are shown)
For equilibrium of B
T = f1 + f2 = 25 N
For equilibrium of C
F = T + f2 + f3 = 80 N