Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
534 views
in Laws of motion by (15.3k points)
closed by

In the Figure, the blocks A, B and C have masses 3 kg, 4 kg, and 8 kg respectively. The coefficient of sliding friction between any two surfaces is 0.25. A is held at rest by a massless rigid rod fixed to the wall, while B and C are connected by a light flexible cord passing around a fixed frictionless pulley. Find the force F necessary to drag C along the horizontal surface to the left at a constant speed. Assume that the arrangement shown in the Figure. i.e. B on C and A on B, is maintained throughout. (Take g =10ms2)

2 Answers

+1 vote
by (39.0k points)
selected by
 
Best answer

Maximum friction between A and B = µmAg

or f1 = 0.25(3)(10) = 7.5 N

Maximum friction between B and C = µ(mA + mB)g

or f2 = 0.25 (3 + 4)(10) = 17 5 N

Maximum friction between C and ground

f3 = µ (mA + mB + mC)g

= 0.25(3 + 4 + 8)(10)

= 37.5 N

Block C and hence block B are moving in opposite directions with constant velocities and block A is at rest. Hence, net force no all three blocks should be zero. Free body diagrams have been shown below (Only horizontal forces are shown)

For equilibrium of B

T = f1 + f2 = 25 N

For equilibrium of C

F = T + f2 + f3 = 80 N

+1 vote
by (15.9k points)
edited by

The necessary force to drag C is 37.5 N.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...