Question

A block of mass 2 kg slides on an inclined plane which makes an angle of with the horizontal. The coefficient of friction between the block and the surface is \(\frac{\sqrt{3}}{\sqrt{2}}\). What force along the plane should be applied to the block so that it moves (a) down and (b) up without any acceleration (Take g =10 m /s² )

Answer 1

(a) Force required to move the block down the plane with constant velocity.

F₁ will be acting downwards, while F₂ upwards.

Since F₂ > F₁, force required

F = F₂ – F₁ = 11.21 N

(b) Force required to move the block up the plane with constant velocity

F₁ and F₂ both will be acing downwards.

F = F₁ + F₂ = 31.21 N

Answer 2

force

Answer 3

Required force a = 11.21 N, b = 31.21N