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in Laws of motion by (15.3k points)
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A hemispherical bowl of radius R = 0.1 m is rotating about its own axis (which is vertical) with an angular velocity ω. A particle of mass10−2 kg on the frictionless inner surface of the bowl is also rotating with the same ω. The particle is at height h from the bottom of the bowl. 

(a) Obtain the relation between h and ω. What is the minimum value of ω needed, in order to have a nonzero value of h? 

(b) It is desired to measure (acceleration due to gravity) using the setup by measuring h accurately. Assuming that R and ω are known precisely and that the least count in the measurement of h is 10-4 m, what is minimum possible error ∆g in the measured value of g?

2 Answers

+1 vote
by (39.0k points)
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Best answer

Given : R = 0 1m, m = 10–2 kg

(a) FBD of particle in ground frame of reference is shown in figure. Hence,

Therefore, minimum value of ω should be

(b) Eq. (iii) can be written as h = \(R -\frac g{\omega^2}\)

If R and ω are known precisely, then

+1 vote
by (15.9k points)

Answer is :

(a) 9.89 rad/sec, 

(b) 9.8 \(\times\) 10-3 m/s2

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