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A 10 g bullet travelling at 200 m/s strikes and remains embedded in a 2 kg target which is originally at rest but free to move. At what speed does the target move off ?

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Mass of bullet, m1 = 10g = 0.01 kg

Velocity of bullet v1 = 200 m/s

Mass of block with the bullet as bullet gets embedded in it, m2 = 2+0.01 = 2.01 kg

Recoil velocity v2

According to the law of conservation of momentum m1 x v1 = m2 x v2

0.01 x 200 = 2.01 x v2

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