We have, OA = OB = AB

Therefore, ∆OAB is a equilateral triangle.

⇒ ∠AOB = 60°

We know that angle subtended by an arc at the centre of a circle is double the angle subtended by the same arc on the remaining part of the circle.

∴ ∠AOB = 2∠ACB

⇒ ∠ACB = 1/ 2 ∠AOB = 1/ 2 × 60°

⇒ ∠ACB = 30°

Also, ∠ADB = 1/ 2 reflex ∠AOB

= 1/ 2 (360° – 60°) = 1/ 2 × 300° = 150°

Hence, angle subtended by the chord at a point on the minor arc is 150° and at a point on the major arc is 30° **Ans**