Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
3.6k views
in Mathematics by (30.0k points)

A chord of a circle is equal to the radius of the circle. Find the angle subtended by the chord at a point on the minor arc and also at a point on the major arc.

1 Answer

0 votes
by (130k points)
selected by
 
Best answer

We have, OA = OB = AB 

Therefore, ∆OAB is a equilateral triangle. 

⇒ ∠AOB = 60° 

We know that angle subtended by an arc at the centre of a circle is double the angle subtended by the same arc on the remaining part of the circle. 

∴ ∠AOB = 2∠ACB 

⇒ ∠ACB = 1/ 2 ∠AOB = 1/ 2 × 60° 

⇒ ∠ACB = 30° 

Also, ∠ADB = 1/ 2 reflex ∠AOB 

= 1/ 2 (360° – 60°) = 1/ 2 × 300° = 150° 

Hence, angle subtended by the chord at a point on the minor arc is 150° and at a point on the major arc is 30° Ans

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...