Question

Class 7 Maths MCQ Questions for Data Handling with Answers?

Answer 1

Practice Class 7 Maths MCQ Questions for Data Handling with Answers and score high in exams. MCQ Questions for Class 7 Maths with Answers were prepared based on the latest exam pattern. We have provided Data Handling Class 7 Maths MCQ Questions with Answers to help students understand the concept very well.

Our teachers have provided here collection of multiple choice questions for Fractions and Decimals Class 7 covering whole syllabus of your textbook. Practicing such MCQ Questions would give you added confidence while attempting your exam and test your knowledge and evaluate yourself.

Practice MCQ Questions for Class 7 Maths

1. If a coin is flipped in the air, what is the probability of getting a head?

(a) 0
(b) 1/2
(c) 1
(d) 2

2. A bag has 4 red balls and 4 green balls, what is the probability of getting a green ball randomly?

(a) 1/4
(b) 1/8
(c) 1/2
(d) 0

3. Pictorial representation of data using symbols is known as:

(a) Bargraph
(b) Pictograph
(c) Piechart
(d) None of these

4. Check the given table, and give the correct answer to the question.

Range of Marks Obtained	Number of students
No. of hours	No. of Students
250 - 300	10
300 - 350	12
350 - 400	14
400 - 450	13
450 - 500	11

What is the total number of students for all ranges?

(a) 12
(b) 14
(c) 50
(d) 60

5. A die is thrown. What is the probability of getting an even prime number?

(a) 1/2
(b) 1/4
(c) 1/6
(d) 6/9

6. Find the class mark of class interval 40−50.

(a) 56
(b) 55
(c) 36
(d) 45

7. The central total angle in a pie chart is

(a) 180º
(b) 210º
(c) 360º
(d) None of these

8. A bag contains 3 red and 5 black. A ball is drawn at random from the bag. What is the probability that the ball drawn is black

(a) 3/6
(b) 5/8
(c) 1/6
(d) 3/8

9. A child has a block in the shape of a cube with one letter written on each face as shown below:

(a) 1/3
(b) 1/6
(c) 1/2
(d) 1/4

10. Three dice are thrown together. Find the number of outcomes.

(a) 216
(b) 256
(c) 366
(d) 300

11. The number of tourists visiting a historical place in a week is shown in the following table :

Day	Number of tourists
Monday	65
Tuesday	72
Wednesday	98
Thursday	84
Friday	60
Saturday	108
Sunday	160

What is the difference between the number of tourists visiting on Friday and Monday?

(a) 10
(b) 24
(c) 38
(d) 5

12. A batsman scored the following number of runs in six innings: 35, 30, 45, 65, 39, 20. The mean runs scored by him in an inning is

(a) 39
(b) 38
(c) 37
(d) 40

13. The mean of the numbers 10,20, 30, and 40 is

(a) 20
(b) 25
(c) 30
(d) 50

14. The range of the weights (in kg) of students of a class given below is: 49, 60, 47, 50, 47, 59, 58, 45, 53

(a) 10
(b) 15
(c) 20
(d) 2

15. The mode of the distribution 3,5, 7, 4, 2, 1, 4, 3, 4 is

(a) 7
(b) 4
(c) 3
(d) 1

16. Median of distribution 2, 3, 4, 7, 5, 1 is:

(a) 4
(b) 7
(c) 11
(d) 3.5

17. Read the following bar graph and answer the following related questions :

The difference between the maximum and minimum marks is

(a) 100
(d) 200
(c) 400
(d) 500

18. Sale of Mathematics and English books in the year 2005, 2006, 2007, and 2008 are given below: Answer the following related question :

Years	Mathematics	English
2005	200	100
2006	300	250
2007	400	200
2008	500	500

The rise in the sale of Mathematics books from 2005 to 2008 is

(a) 100
(b) 200
(c) 300
(d) 400

19. The number of tourists visiting a historical place in a week is shown in the following table :

Day	Number of tourists
Monday	65
Tuesday	72
Wednesday	98
Thursday	84
Friday	60
Saturday	108
Sunday	160

The sum of the number of tourists visiting on Sunday and Friday is

(a) 160
(b) 60
(c) 220
(d) 100

20. Mean of the first six prime numbers is

(a) 7.83
(b) 5.83
(c) 6.83
(d) 4.83

21. The data which is collected directly from the source is called

(a) primary data
(b) ungrouped data
(c) grouped data
(d) secondary data

22. The mean of the first ten natural ………………. numbers is

(a) 6.5
(b) 5.5
(c) 7.5
(d) 8.5

23. What is called one or more outcomes of an experiment?

(a) Space
(b) Experiment
(c) Sample
(d) Event

24. The probability of an experiment cannot be greater than :

(a) 0
(b) 0.5
(c) 1
(d) 2

25. The mean of 6, y, 7, x, and 14 is 8. Which of the following is true?

(a) x+y = 13          
(b) x−y = 13
(c) 2x+3y = 13   
(d) x²+y = 1

Answer 2

1. Answer: (b) 1/2

Explanation: A coin has two sides, Head and tails.

Hence, probability = Number of possible outcomes/Total number of outcomes

We know, Tail is present on one side of a coin and in total there could be two outcomes H&T

Hence, Probability = 1/2

2. Answer: (c) 1/2

Explanation: Total number of balls in bag = 4 + 4 = 8

Total number of green balls = 4

Probability of getting a green ball

= 4/8 

= 1/2

3. Answer: (b) Pictograph

Explanation: The information presented through pictures or symbols of different objects is called the pictorial representation of data. The pictures of different objects are used to represent different information and thus such pictorial data are called pictographs.

4. Answer: (d) 60

Explanation: Total number of students

= 10 + 14 + 12 + 13 + 11

= 60

5. Answer: (c) 1/6

Explanation: Explanation: When a die is thrown,

Number of total possible outcomes = 6

Number of even prime numbers = 1 (2 is the only even prime number)

Thus, the probability of getting an even prime number,

P = 1/6

6. Answer: (d) 45

Explanation: \(Class\; mark = \frac{Lower\; limit + Upper\; limit}{2}\)

Given class interval is 40-50

⇒  Lower limit = 40 and upper limit = 50

Class mark = 40 + 50/2

 = 90/2

= 45

7. Answer: (c) 360º

Explanation: The total angle at the centre of the circle is 360º.

8. Answer: (b) 5/8

Explanation: Total no. of balls = 3+5 = 8

No. of red balls = 3

No. of black balls = 5

P(getting a red ball) = No of black balls / Total no of balls

= 5/8

9. Answer: (a) 1/3

Explanation: Probability

= 2/6 

= 1/3

10. Answer: (a) 216

Explanation: Two dices are thrown together

For one dice the number of outcomes are 6 i.e 1,2,3,4,5,6

Similarly for the second and third dice the number of outcomes will be 6 and 6

Hence when all three dices are thrown together

The total number of outcomes

=(6×6×6)

= 216

11. Answer: (d) 5

Explanation: Friday tourist number = 60

Monday tourist number = 65

65 – 60 

= 5.

12. Answer: (a) 39

Explanation: Mean = \(\frac{35+30+45+65+39+20}{6}\)

\(=\frac{234}{6}\)

= 39

13. Answer: (b) 25

Explanation: Mean = \(\frac{10+20+30+40}{4}\)

\(=\frac{100}{4}\)

= 25

14. Answer: (b) 15

Explanation: Range = 60 – 45 

= 15.

15. Answer: (b) 4

Explanation: 4 has the highest frequency of 3. So 4 is the mode

Observation	Frequency
3	2
5	1
7	1
4	3
2	1
1	1

16. Answer: (d) 3.5

Explanation: Arranging the terms in ascending order 1, 2, 3, 4, 5, 7

Here No. of terms is 6 which is even

Thus, Median \(\frac{\frac{n}{2}^{th}\;term+(n+1)^{th}\;term}{2}\)

= \(\frac{\frac{6^{th}}{2}\;term+(\frac{6}{2}+1)^{th}\;term}{2}\)

= \(\frac{3^{rd}\;term+4^{th}\;term}{2}\)

= \(\frac{3+4}{2}\)

= 7/2

= 3.5

17. Answer: (d) 500

Explanation: 600 – 100 

= 500.

18. Answer: (c) 300

Explanation: 500 – 200 

= 300.

19. Answer: (c) 220

Explanation: 160 + 60 

= 220.

Answer 3

 20. Answer: (c) 6.83

Explanation: First 6 prime numbers are 2,3,5,7,11,13

Here, n=6

\(\Sigma X_i/n=\frac{(2+3+5+7+11+13)}{6}\)

= 41/6

= 6.83

Therefore, the mean of the first six prime numbers is 6.83

21. Answer: (a) primary data

Explanation:  Primary data is a type of data that is collected by researchers directly from main sources through interviews, surveys, experiments, etc. Primary data are usually collected from the source.

22. Answer: (b) 5.5

Explanation: Sum of first ten Natural numbers = \(\frac{n(n+1)}{2},\) where n = 10

\(=\frac{10(11)}{2}\)

= 55

Now  Mean of first ten Natural number = \(\frac{55}{10}\)

= 5.5

23. Answer: (d) Event

Explanation: An event is called one or more outcomes of an experiment.

Example: rolling a dice, we get a possible outcomes as {1,2,3,4,5,6}.

24. Answer: (c) 1

Explanation: The maximum probability an event can have is 

\(=\frac{100}{100}\)

 = 1

25. Answer: (a) x+y = 13

Explanation: The mean of the 5 numbers 6,y,7,x,14 is 8.

Mean = \(\frac{number\;of\;observations}{total\;observation}\)

\(8=\frac{6+y+7+x+14}{5}\)

40 = 27+y+x

y+x = 13

y =13−x

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