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Class 7 Maths MCQ Questions for Algebraic Expressions with Answers?

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Class 7 Maths MCQ Questions for Algebraic Expressions with Answers accessible here. The MCQ Questions for Class 7 Algebraic Expressions with solutions had been organized as in step with the modern syllabus, NCERT books, and exam pattern recommended through CBSE in class 7. Multiple Choice Questions are a vital part of exams for class 7 Algebraic Expressions and if practiced nicely can help you get better marks. Class 7 Algebraic Expressions students must seek advice from the following multiple-choice questions with solutions for Algebraic Expression. These MCQ Questions for class 7  Maths with solutions will are available assessments and assist you to attain proper marks.

Students are recommended to resolve Algebraic Expressions Multiple Choice Questions of Class 7 Maths to recognize specific concepts. Practicing the MCQ Questions on Algebraic Expressions Class 7 with detailed solutions will improve your self-belief thereby supporting your rating properly withinside the exam.

Practice MCQ Questions for Class 7 Maths

1. How many terms are there in the expression 7x3+2xy+z−7y?

(a) 3
(b) 4
(c) 5
(d) 6

2. How many terms are there in the expression – 2p3 – 3p2 + 4p + 7?

(a) 1
(b) 2
(c) 3
(d) 4

3. What is the coefficient of x in the expression 4x + 3y?

(a) 1
(b) 2
(c) 3
(d) 4

4. The value of the expression x+ y3 when x=2 and y=-2 is 

(a) 0
(b) 8
(c) 16
(d) -16

5. The value of x2 – 2x + 1 when x = 1 is

(a) 1
(b) 2
(c) -2
(d) 0

6. The result of subtraction of 3x from -4x is

(a) -7x
(b) 7x
(c) x
(d) -x

7. The volume of a cube of side 2a is

(a) 4a2
(b) 2a
(c) 8a3
(d) 8

8. If we add, 7xy + 5yz – 3zx, 4yz + 9zx – 4y and -3xz + 5x – 2xy, then the answer is:

(a) 5xy + 9yz + 3zx + 5x – 4y
(b) 5xy – 9yz + 3zx – 5x – 4y
(c) 5xy + 10yz + 3zx + 15x – 4y
(d) 5xy + 10yz + 3zx + 5x – 6y

9. Which of the following is like term as 7xy?

(a) 9
(b) 9x
(c) 9y
(d) 9xy

10. If a + b + c = 9 and ab + bc + ca = 26, then the value of a3 + b3 + c3 – 3abc

(a) 27
(b) 29
(c) 729
(d) 495

11. Add 2 mn, -4 mn, 8 mn, -6 mn

(a) 0
(b) 2 mn
(c) 8 mn
(d) 10 mn

12. Add 4x2y, -3x2y, -7xy2, 7xy2

(a) x2y
(b) xy2
(c) xy
(d) -x2y

13. Simplify : p + (p – q) + q + (q – p)

(a) p
(b) q
(c) p + q
(d) p – q

14. Simplify : z2 + 11z2 – 5z – 11z2 + 5z

(a) z2
(b) -z2
(c) 5z
(d) -5z

15. Subtract – xy from xy

(a) xy
(b) 2xy
(c) 3xy
(d) 4xy

16. Subtract y2 from – 5y2

(a) -6y2
(b) 6y2
(c) y2
(d) -5y

17. Find the value of the expression x + 2 for x = -2

(a) 0
(b) 2
(c) -2
(d) 4

18. Find the value of the expression 100 – 10 x 3 for x = 0

(a) 10
(b) -10
(c) 100
(d) -10

19. Find the value of the expression x2 + 2x + 1 for x = – 1

(a) 0
(b) 1
(c) -1
(d) 2

20. If the value of the expression x2 – 5x + k for x = 0 is 5, then the value of k is

(a) 2
(b) 3
(c) 4
(d) 5

21. Simplify the expression 10−3b−4−5b and find their values if x=3,a=−1,b=−2 

(a) 22
(b) 33
(c) 45
(d) 5

22. When a certain number m, is divided by 5 and added to 8, the result is equal to 3m subtracted from 4. The value of m is

(a) 3/4
(b) 3/6
(c) -5/4
(d) 5/6

23. A rectangular plot has a concrete path running in the middle of the plot parallel to parallel to the breadth of the plot. The rest of the plot is used as a lawn, which has an area of 240sq. m. If the width of the path is 3m and the length of the plot is greater than its breadth by 2m, what is the area of the rectangular plot(in m )?

(a) 288 sq. m
(b) 488 sq. m
(c) 388 sq. m
(d) 588 sq. m

24. The constant term in the expression 1 + x2+ x is

(a) 1
(b) x
(c) x2
(d) None of these

25. In a two-digit number, the units digit is x and the tens digit is y. Then the number is 

(a) 10y + x
(b) 10x + y
(c) 10y - x
(d) 10x -y

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Answer:

1. Answer: (b) 4

Explanation: There are 4 terms. The terms are 7x3,2xy,z,7y

2.  Answer: (d) 4

Explanation: There are 4 terms. The terms are – 2p,– 3p2,4p,7

3.  Answer: (d) 4

Explanation:  The coefficient of x in the expression 4x + 3y is 4.

4.  Answer: (a) 0

Explanation:  Value of x3+y3

=(2)3+(−2)3

=8−8

=0

5.  Answer: (d) 0

Explanation:  Value = (1)2 – 2(1) + 1 

= 0

6.  Answer: (a) -7x

Explanation: -4x -3x 

= -7x

7.  Answer: (c) 8a3

Explanation: Volume = 2a × 2a × 2a

= 8a3

8.  Answer: (a) 5xy + 9yz + 3zx + 5x – 4y

Explanation:  Given, 7xy + 5yz – 3zx, 4yz + 9zx – 4y and -3xz + 5x – 2xy.

If we add the three expressions, then we need to combine the like terms together.

(7xy – 2xy)+(5yz + 4yz) – 3zx + 9zx – 3xz – 4y + 5x

= 5y + 9yz + 3zx + 5x – 4y

9.  Answer: (d) 9xy

Explanation:  The terms which have the same literal coefficients raised to the same powers but may only differ in numerical coefficient are like terms.

10.  Answer: (a) 27

Explanation:  ⇒ (a + b + c)2 = 81 [On squaring both sides of (i)]  

⇒ a2 + b2 + c2 + 2(ab + bc + ac) = 81  

⇒ a2 + b2 + c2 + 2 × 26 = 81 [∵ab + bc + ac = 26]  

⇒ a2 + b2 + c2 = (81 - 52)  

⇒ a2 + b2 + 2 = 29.  

Now, we have 

a3 + b3 + c3 - 3abc = (a + b + c) (a2 + b2 + c2 - ab - bc - ac)   

= (a + b + c) [(a2 + b2 + c2 ) - (ab + bc + ac)]   

= 9 × [(29 - 26)]   

= (9 × 3)   

= 27

11.  Answer: (a) 0

Explanation: 2mn + (-4mn) + 8mn + (-6)mn 

= 0

12.  Answer: (a) x2y

Explanation: (4 – 3)xy + (-7 +7)xy2 

= x2y

13. Answer: (c) p + q

Explanation:  p + p – q + q + q – p 

= p + q

14.  Answer: (b) -z2

Explanation:  (-1 + 11 – 11)z2 + (5 – 5)z 

= -z2

15.  Answer: (b) 2xy

Explanation: xy – (-xy) = xy + xy 

= 2xy

16.  Answer: (a) -6y2

Explanation: -5y2 – y2 

= -6y2

17.  Answer: (a) 0

Explanation: Given x = -2

-2 + 2 

= 0

18.  Answer:(c) 100

Explanation: Given x = 0

100 – 10(0)3 

= 100

19.  Answer: (a) 0

Explanation:  Given x = -1

(-1)2 + 2(-1) + 1 

= 0

20.  Answer: (d) 5

Explanation: Given x = 0

(0)2 – 5(0) + k = 5

⇒ k = 5

21.  Answer: (a) 22

Explanation: 10−3b−4−5b

⇒ (10−4)−(3b+5b)

⇒ 6−8b

⇒ 6−8(−2)

⇒ 22.

22.  Answer: (c) -5/4

Explanation: m is divided by 5 and add to 8 gives 8 + m/5.

And is equal to 3m subtracted from 4 i.e. equal to 4−3m.

Then 4−3m = 8 + m/5

⇒ 20−15m=40+m

⇒ 20−40=m+15m

⇒ −20=16m

m = \(-\frac{5}{4}\)

23. Answer: (a) 288 sq. m

Explanation:  Let the width be x ma nd length be (x+2)m

Area of path = 3x sq. m

= x(x+2)−3x=240

⇒ x2+2x−3x = 240

⇒ x2−x−240=0

⇒ x2−16x+15x−240=0

⇒ x(x−16)+15(x−16)=0

⇒ x+15=0,x−16=0

∴x=16

Length = 16+2=18m

∴ Area of the plot = 16×18 = 288 sq. m

24.  Answer: (a) 1

Explanation: The constant term in the expression 1 + x2+ x is 1

25. Answer: (a) 10y + x

Explanation:  Suppose our number is 53.It has 3 at units digit and 5 as tens digit
So 53 can be written as 10×5+3

Similarlly any 2 digit number  say 'yx' with x at units digit and y as tens digit  which can be written as 10x+y

Another approach is say our number is yx then by dividing it with 10 we get remainder x and quotient as y

So we know that dividend=divisor×quotient+remainder

So xy = 10×y+x

Click here for Practice MCQ Questions for Algebraic Expressions Class 7

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