Question

Find three consecutive terms in an A.P. whose sum is –3 and the product of their cubes is 512.

Answer 1

Let the three consecutive terms in an A.P be a – d, a and a + d

According to the first condition,

 a – d + a + a + d = –3

\(\therefore\) The three consecutive terms of an A.P. are –4, –1 and 2 or 2, –1 and –4.