Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.2k views
in Arithmetic Progression by (40.3k points)
closed by

Mary got a job with a starting salary of Rs. 15,000/- per month. She will get an increment of Rs.100/- per month. What will be her salary after 20 months?

1 Answer

+1 vote
by (38.4k points)
selected by
 
Best answer

Mary’s salaries are in A.P. with the first term 15,000 and common difference 100.

\(\therefore\) a = 15000, d = 100, n = 20

Now, tn = a + (n – 1) d

\(\therefore\) t20 = 15000 + (20 – 1) 100

= 15000 + 19 x 100

= 15000 + 1900

= 16900

\(\therefore\) Mary’s salary after 20 months will be Rs.16,900.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...