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in Arithmetic Progression by (40.4k points)
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The taxi fare is Rs.14 for the first kilometre and Rs. 2 for each additional kilometre. What will be the fare for 10 kilometres?

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The taxi fares are in A.P. with the first term 14 and common difference 2.

\(\therefore\) a = 14, d = 2, n = 10

Now, tn = a + (n – 1) d

\(\therefore\) t10 = 14 + (10 – 1) x 2

= 14 + 9 x 2

= 32

\(\therefore\) The taxi fare for 10 kilometres will be Rs.32.

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