The taxi fares are in A.P. with the first term 14 and common difference 2.
\(\therefore\) a = 14, d = 2, n = 10
Now, tn = a + (n – 1) d
\(\therefore\) t10 = 14 + (10 – 1) x 2
= 14 + 9 x 2
= 32
\(\therefore\) The taxi fare for 10 kilometres will be Rs.32.