Vertices of triangle ABC are A (8,-8), B (6,8) and C (2,4).
∵ A median of a triangle is a line segment drawn from a vertex to the midpoint of the opposite side of the vertex median from vertex A is :
AD = \(\sqrt{(4-8)^2+(6+8)^2}\)
= \(\sqrt{16+196}\)
= \(\sqrt{212}\)
= \(4\sqrt{53}\) unit.
Median from vertex B is :
BE = \(\sqrt{(6-5)^2+(8+2)^2}\)
= \(\sqrt{1+100}\)
= \(\sqrt{101}\) unit.
Median from vertex C is :
CF = \(\sqrt{(7-2)^2+(0-4)^2}\)
= \(\sqrt{25+16}\)
= \(\sqrt{41}\) unit.