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The acceleration due to gravity on the surface of moon is 1.7 ms–2 . What is the time period of a simple pendulum on the surface of moon if its time period on the surface of earth is 3.5 s? (g on the surface of earth is 9.8 ms–2 )

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Acceleration due to gravity on the surface of moon, g = 1.7 m s–2 

Acceleration due to gravity on the surface of earth, g = 9.8 m s–2 

Time period of a simple pendulum on earth, T = 3.5 s 

T = 2π √l/g

Where, l is the length of the pendulum

Hence, the time period of the simple pendulum on the surface of moon is 8.4 s. 

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