Question

In an experiment four quantities a, b, c and d are measured with percentage error 1%, 2%, 3% and 4% respectively. Quantity P is calculated as follows:

P = \(\frac{a^3b^2}{cd}\) .% error in P is

(A) 14% 

(B) 10% 

(C) 7% 

(D) 4%

Answer 1

Answer is (A) 14%

Given that: P = \(\frac{a^3b^2}{cd}\) 

∴ Percentage error in P is given as,

\(\frac{Δp}{p}\times100\) = (error contributed by a)+(error contributed by b) + (error contributed by c) + (error contributed by d) 

= 3% + 4% + 3% + 4% 

= 14%