1,4, 7, 10,…
f = 1, d = 3
xn = dn + (f – d) = 3n + (1 – 3) = 3n – 2
When 4 is divided by 3 we get remainder as 1 When 100 is divided by 3 we get remainder as 1
So, 100 is a term of the arithmetic sequence.
Square = (3n – 2)2 = 9n2 – 12n + 4 (9n2 – 12n + 4) + 3
When 9n2 – 12n + 4 is divided by 3the remainder is 1.
So square of the term also in the sequence.
∴ The square of any term of this sequence belongs to that sequence.