Here, a = 10 cm, l = 12.5 cm, b = 10 cm, h = 8 cm

(i) Lateral surface area of the cubical box = 4a^{2}

= 4 × (10)2 cm^{2} = 400 cm^{2 }

Lateral surface area of the cuboidal box = 2h (l + b)

= 2 × 8 (12.5 + 10) cm^{2 }

= 16 × 22.5 cm2 = 360 cm^{2 }

Difference in the lateral surface areas of the two boxes

= (400 – 360) cm^{2} = 40 cm^{2}.

Hence, the cubical box has greater lateral surface area by 40 cm^{2}. **Ans. **

(ii) Total surface area of the cubical box = 6a^{2}

= 6 × (10)^{2} cm^{2} = 600 cm^{2}

Total surface area of the cuboidal box = 2(lb + bh + hl)

= 2(12.5 × 10 + 10 × 8 + 8 × 12.5) cm^{2}

= 2(125 + 80 + 100) cm^{2}

= 2 × 305 cm^{2} = 610 cm^{2}

Difference in the total surface areas of the two boxes = (610 – 600) cm^{2 }

= 10 cm^{2}

Hence, the cubical box has smaller total surface area by **10 cm**^{2} Ans