Question

Parveen wanted to make a temporary shelter for her car, by making a boxlike structuer with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5 m, with base dimesions 4 m × 3 m?

Answer 1

Here, l = 4 m, b = 3 m, h = 2.5 m 

The tarpaulin is needed to cover 5 faces only (excluding the floor)

Surface area of the shelter = lb + 2 (bh + hl) 

= 4 × 3 m² + 2(3 × 2.5 + 2.5 × 4) m² 

= 12 m² + 2(7.5 + 10) m² = (12 + 35) m² = 47 m² 

Hence, 47 m² of tarpaulin is required to make the shelter Ans.