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+1 vote
16.2k views
in Mathematics by (30.0k points)

The inner diameter of a circular well is 3.5 m. It is 10 m deep. Find 

(i) its inner curved surface area, 

(ii) the cost of plastering this curved surface at the rate of Rs 40 per m2

1 Answer

+1 vote
by (130k points)
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Best answer

Here, r = 3. 5/ 2 m , h = 10 m 

(i) Inner curved surface area of the well 

= 2πrh = 2 × 22/ 7 × 3. 5 /2  × 10m2 

= 22 × 5 m2 = 110 m2 Ans. 

(ii) Cost of plastering 1 m2 = Rs 40 

∴ Cost of plastering the curved surface area of the well 

= Rs 110 × 40 = Rs 4400 Ans

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