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in Arithmetic Progression by (43.8k points)
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Find the 19th term of the A.P. 7,13,19,25,….

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Correct Answer - The 19th term is 115.
Here ` a= t_(1) = 7, t_(2) = 13, t_(3) = 19 , t_(4)= 25,…`
`d= t_(2) - t_(1) = 13-7=6, n = 19`
`t_(n) = a+ ( n -1) d ` …(Formula)
`:. T_(19) = 7 + ( 19-1) xx6` …( Substituting the values )
`= 7 + 18 xx 6`
`= 7 + 108`
` = 115`

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